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55 lines
2.4 KiB
OCaml
55 lines
2.4 KiB
OCaml
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(** {2 Test sequences} *)
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(** print a list of items using the printing function *)
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let pp_list ?(sep=", ") pp_item formatter l =
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Sequence.pp_seq ~sep pp_item formatter (Sequence.List.to_seq l)
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(** Set of integers *)
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module ISet = Set.Make(struct type t = int let compare = compare end)
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module ISetSeq = Sequence.Set(ISet)
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let sexpr = "(foo bar (bazz quux hello 42) world (zoo foo bar (1 2 (3 4))))"
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let _ =
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let l = [0;1;2;3;4;5;6] in
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let l' = Sequence.List.of_seq
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(Sequence.filter (fun x -> x mod 2 = 0) (Sequence.List.to_seq l)) in
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let l'' = Sequence.List.of_seq
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(Sequence.take 3 (Sequence.drop 1 (Sequence.List.to_seq l))) in
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let h = Hashtbl.create 3 in
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for i = 0 to 5 do
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Hashtbl.add h i (i*i);
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done;
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let l2 = Sequence.List.of_seq
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(Sequence.map (fun (x, y) -> (string_of_int x) ^ " -> " ^ (string_of_int y))
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(Sequence.Hashtbl.to_seq h))
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in
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let l3 = Sequence.List.of_seq (Sequence.rev (Sequence.Int.range ~start:0 ~stop:42)) in
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let set = List.fold_left (fun set x -> ISet.add x set) ISet.empty [4;3;100;42] in
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let l4 = Sequence.List.of_seq (ISetSeq.to_seq set) in
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Format.printf "l=@[<h>[%a]@]@." (pp_list Format.pp_print_int) l;
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Format.printf "l'=@[<h>[%a]@]@." (pp_list Format.pp_print_int) l';
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Format.printf "l''=@[<h>[%a]@]@." (pp_list Format.pp_print_int) l'';
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Format.printf "l2=@[<h>[%a]@]@." (pp_list Format.pp_print_string) l2;
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Format.printf "l3=@[<h>[%a]@]@." (pp_list Format.pp_print_int) l3;
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Format.printf "s={@[<h>%a@]}@." (Sequence.pp_seq Format.pp_print_int) (ISetSeq.to_seq set);
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Format.printf "l4=@[<h>[%a]@]@." (pp_list Format.pp_print_int) l4;
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Format.printf "l3[:5]+l4=@[<h>[%a]@]@." (Sequence.pp_seq Format.pp_print_int)
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(Sequence.Array.to_seq
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(Sequence.Array.of_seq (Sequence.append
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(Sequence.take 5 (Sequence.List.to_seq l3)) (Sequence.List.to_seq l4))));
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(* sum *)
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let n = 100000000 in
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let sum = Sequence.fold (+) 0 (Sequence.take n (Sequence.repeat 1)) in
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Format.printf "%dx1 = %d@." n sum;
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assert (n=sum);
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let s = Sexpr.of_seq (Sexpr.lex (Sequence.String.to_seq sexpr)) in
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let s = Sexpr.of_seq (Sequence.map
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(function | `Atom s -> `Atom (String.capitalize s) | tok -> tok)
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(Sexpr.traverse s))
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in
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Format.printf "@[<hov2>transform @[<h>%s@] into @[<h>%a@]@]@." sexpr (Sexpr.pp_sexpr ~indent:false) s;
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Format.printf "@[<hv2> cycle:%a@]@." Sexpr.pp_tokens
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(Sequence.concat (Sequence.take 10 (Sequence.repeat (Sexpr.traverse s))));
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()
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