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172 lines
5.3 KiB
OCaml
172 lines
5.3 KiB
OCaml
(** {2 Test iterators} *)
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(** print a list of items using the printing function *)
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let pp_list ?(sep = ", ") pp_item formatter l =
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Iter.pp_seq ~sep pp_item formatter (Iter.of_list l)
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(** Set of integers *)
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module ISet = Set.Make (struct
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type t = int
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let compare = compare
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end)
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let iset = (module ISet : Set.S with type elt = int and type t = ISet.t)
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module OrderedString = struct
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type t = string
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let compare = compare
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end
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module SMap = Iter.Map.Make (OrderedString)
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let my_map = SMap.of_seq (Iter.of_list [ "1", 1; "2", 2; "3", 3; "answer", 42 ])
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let sexpr = "(foo bar (bazz quux hello 42) world (zoo foo bar (1 2 (3 4))))"
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type term =
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| Lambda of term
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| Const of string
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| Var of int
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| Apply of term * term
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let random_term () =
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let max = 10 and num = ref 0 in
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let rec build depth =
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if depth > 4 || !num > max then
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Const (random_const ())
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else (
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match Random.int 6 with
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| 0 ->
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if depth > 0 then
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Var (Random.int depth)
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else
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Const (random_const ())
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| 1 ->
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incr num;
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Lambda (build (depth + 1))
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| 2 -> Const (random_const ())
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| _ ->
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incr num;
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Apply (build depth, build depth)
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)
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and random_const () = [| "a"; "b"; "c"; "f"; "g"; "h" |].(Random.int 6) in
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build 0
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let rec sexpr_of_term t =
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let f t k =
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match t with
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| Var i -> Sexpr.output_str "var" (string_of_int i) k
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| Lambda t' -> Sexpr.output_seq "lambda" (sexpr_of_term t') k
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| Apply (t1, t2) ->
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Sexpr.output_seq "apply"
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(Iter.append (sexpr_of_term t1) (sexpr_of_term t2))
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k
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| Const s -> Sexpr.output_str "const" s k
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in
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Iter.from_iter (f t)
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let term_parser =
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let open Sexpr in
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let rec p_term () =
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left
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>> ("lambda", p_lambda) ^|| ("var", p_var) ^|| ("const", p_const)
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^|| ("apply", p_apply) ^|| fail "bad term"
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>>= fun x -> right >> return x
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and p_apply () =
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p_term () >>= fun x ->
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p_term () >>= fun y -> return (Apply (x, y))
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and p_var () = p_int >>= fun i -> return (Var i)
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and p_const () = p_str >>= fun s -> return (Const s)
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and p_lambda () = p_term () >>= fun t -> return (Lambda t) in
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p_term ()
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let term_of_sexp seq = Sexpr.parse term_parser seq
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let test_term () =
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let t = random_term () in
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Format.printf "@[<h>random term: %a@]@." Sexpr.pp_tokens (sexpr_of_term t);
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let tokens = sexpr_of_term t in
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let t' = term_of_sexp tokens in
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Format.printf "@[<h>parsed: %a@]@." Sexpr.pp_tokens (sexpr_of_term t');
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()
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let _ =
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(* lists *)
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let l = [ 0; 1; 2; 3; 4; 5; 6 ] in
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let l' = Iter.to_list (Iter.filter (fun x -> x mod 2 = 0) (Iter.of_list l)) in
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let l'' = Iter.to_list (Iter.take 3 (Iter.drop 1 (Iter.of_list l))) in
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let h = Hashtbl.create 3 in
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for i = 0 to 5 do
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Hashtbl.add h i (i * i)
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done;
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let l2 =
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Iter.to_list
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(Iter.map
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(fun (x, y) -> string_of_int x ^ " -> " ^ string_of_int y)
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(Iter.of_hashtbl h))
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in
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let l3 = Iter.to_list (Iter.rev (Iter.int_range ~start:0 ~stop:42)) in
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let set =
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List.fold_left (fun set x -> ISet.add x set) ISet.empty [ 4; 3; 100; 42 ]
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in
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let l4 = Iter.to_list (Iter.of_set iset set) in
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Format.printf "l=@[<h>[%a]@]@." (pp_list Format.pp_print_int) l;
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Format.printf "l'=@[<h>[%a]@]@." (pp_list Format.pp_print_int) l';
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Format.printf "l''=@[<h>[%a]@]@." (pp_list Format.pp_print_int) l'';
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Format.printf "l2=@[<h>[%a]@]@." (pp_list Format.pp_print_string) l2;
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Format.printf "l3=@[<h>[%a]@]@." (pp_list Format.pp_print_int) l3;
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Format.printf "s={@[<h>%a@]}@."
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(Iter.pp_seq Format.pp_print_int)
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(Iter.of_set iset set);
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Format.printf "l4=@[<h>[%a]@]@." (pp_list Format.pp_print_int) l4;
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Format.printf "l3[:5]+l4=@[<h>[%a]@]@."
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(Iter.pp_seq Format.pp_print_int)
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(Iter.of_array
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(Iter.to_array
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(Iter.append (Iter.take 5 (Iter.of_list l3)) (Iter.of_list l4))));
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(* iterator, persistent, etc *)
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let seq = Iter.int_range ~start:0 ~stop:100000 in
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let seq' = Iter.persistent seq in
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Format.printf
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"test length [0..100000]: persistent1 %d, stream %d, persistent2 %d"
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(Iter.length seq') (Iter.length seq') (Iter.length seq');
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(* maps *)
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Format.printf "@[<h>map: %a@]@."
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(Iter.pp_seq (fun formatter (k, v) ->
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Format.fprintf formatter "\"%s\" -> %d" k v))
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(SMap.to_seq my_map);
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let module MyMapSeq = Iter.Map.Adapt (Map.Make (OrderedString)) in
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let my_map' =
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MyMapSeq.of_seq (Iter.of_list [ "1", 1; "2", 2; "3", 3; "answer", 42 ])
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in
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Format.printf "@[<h>map: %a@]@."
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(Iter.pp_seq (fun formatter (k, v) ->
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Format.fprintf formatter "\"%s\" -> %d" k v))
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(MyMapSeq.to_seq my_map');
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(* sum *)
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let n = 1000000 in
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let sum = Iter.fold ( + ) 0 (Iter.take n (Iter.repeat 1)) in
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Format.printf "%dx1 = %d@." n sum;
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assert (n = sum);
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(* sexpr *)
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let s = Sexpr.of_seq (Sexpr.lex (Iter.of_str sexpr)) in
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let s =
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Sexpr.of_seq
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(Iter.map
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(function
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| `Atom s -> `Atom (String.capitalize_ascii s)
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| tok -> tok)
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(Sexpr.traverse s))
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in
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Format.printf "@[<hov2>transform @[<h>%s@] into @[<h>%a@]@]@." sexpr
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(Sexpr.pp_sexpr ~indent:false)
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s;
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Format.printf "@[<hv2> cycle:%a@]@." Sexpr.pp_tokens
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(Iter.concat (Iter.take 10 (Iter.repeat (Sexpr.traverse s))));
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(* sexpr parsing/printing *)
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for i = 0 to 20 do
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Format.printf "%d-th term test@." i;
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test_term ()
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done;
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()
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